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f(x) = px + q , f(1) = 4 , f(-2) = 1 , nilai  f(-3)+f(3)

f(1) = p+q = 4

f(-2)= -2p+q =1

eliminasi

p+q = 4

-2p+q =1

------------- -

   3p=3

     p=3/3 = 1

substitusi

p+q = 4

q= 4-1 = 3

jadi f(-3)+f(3)

(-3p+q) + (3p+q)

(-3.1 + 3) + (3.1 + 3)

0 + 6

=6