tentukan persamaan garis yg melalui pasangam² titik brikut : P(-1,8)dan Q(3,-2)

(y - y1) / (y2 - y1) = (x - X1) / (x2 - X1)
(y - 8) / (-2 - 8) = (x + 1) / (3 + 1)
(y - 8) / (-10) = (x + 1) / 4
4(y - 8) = (-10)(x + 1)
4y - 32 = - 10x - 10
4y + 10x = - 10 + 32
4y + 10x = 22

[tex] \frac{(y - y1)}{(y2 - y1)} = \frac{(x - x1)}{(x2 - x1)} [/tex]
[tex] \frac{(y - 8)}{( - 2 - 8)} = \frac{(x + 1)}{(3 + 1)} [/tex]
[tex] \frac{(y - 8)}{( - 10)} = \frac{( x+ 1)}{(4)} [/tex]
4(y-8) = (-10)(x+1)
4y-32 = -10x-10
10x+4y-32+10=0
10x+4y-22=0
5x+2y-11=0