Kimia

Pertanyaan

Berapakah [oh-] jika [h+] = 2x 10-3

1 Jawaban

  • pH = - log [H+]
    pH = - log2 . 10-3
    pH = 3 - log2

    pH = 14 - pOH
    3 - log2 = 14 - pOH
    pOH = 11 + log2

    pOH = - log [OH-]
    [OH-] = - 2 . 10-11

    Kalau gak salah kek gitu.

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