Diketahui. Barisan Aritmatika U4=17 U7=29 carilah: U25
Matematika
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Pertanyaan
Diketahui. Barisan Aritmatika U4=17 U7=29 carilah: U25
2 Jawaban
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1. Jawaban ilhamcrucifixoysj7r
diketahui : u4=17 u7=29
ditanyakan : u25
jawab :
U4 : a + 3b = 17
u7 : a + 6b = 29
eliminasi
a + 6b = 29
a + 3b = 17
=> 3b = 12
=> b = 12/3
=> b = 4
subtitusi
a + 3b = 17
a + 3 (4) = 17
a + 12 = 17
a = 17 - 12
a = 5
un = a+(n-1)b
u25 = 5 + (25-1)4
u25 = 5 + (24) 4
u25 = 5 + 96
u25 = 101
koreksi jika salah.
semoga membatu -
2. Jawaban andri77
u4=17
u7=29
dit: u25=...?
jwb:
u7-u4= 29-17
a+6b - (a+3b) = 12
3b=12
b= 12/3 = 4
a+3b=17
a=17 - 3.4
a=17-12 = 5
jadi u25= a+(n-1)b
u25= 5 + 24.4
u25= 5 + 96
u25 = 101