Matematika

Pertanyaan

akar akar persamaan kuadrat
2x² + Mx + 16 = 0 adalah α dan β.
jika α =2β dan α, β positif maka nilai M = ....

1 Jawaban

  • α+β = −b/a = −Μ/2
    α×β = c/a = 16/2

    α = 2β
    2β x β = 16/2
    2β^2 = 8
    β^2 = 8/2
    β^2 = 4
    β = 2

    2β = α
    2(2) = α
    4 = α

    4+2 = -m/2
    6 = -m/2
    12 = -m
    m = -12

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