Matematika

Pertanyaan

Tentukan hasil pemangkatan aljabar berikut
(-7a)²
(8a²b⁴)³
(-4p³q²r)³
(5p⁴q²r³)⁴
(x-10)³
(3x+4)²
(5x-7)²
(-7x+3)²
(2p²+15)²
(-6p²-5q)²
(8p²+3p)²
(7p²-4p)²
(2m-½)²
(4m+¹/m)²
(3m-½m)²
Tlng y

1 Jawaban

  • (-7a)² = 49a²

    (8a²b⁴)³ = 192 a^6 b¹²

    (-4p³q²r)³ = - 64 p^9 q^6 r³

    (5p⁴q²r³)⁴ = 625 p^16 q^8 r¹²

    (3x + 4)² = (3x)² + 2.4.3x + (4)² = 9x² + 24x + 16

    (5x - 7)² = (5x)² + 2.(-7).5x + (-7)² = 25x² - 70x + 49

    (-7x + 3)² = (-7x)² + 2.3(-7x) + (3)² = 49x² - 42x + 9

    (2p² + 15)² = (2p²)² + 2.15.2p² + 15² = 4p⁴ + 60p² + 225

    (-6p² - 5q)² = (-6p)² + 2(-5q)(-6p²) + (-5q)² = 36p² + 60p²q + 25q²

    (8p² + 3p)² = (8p²)² + 2.3p.8p² + (3p)² = 64p⁴ + 480p³ + 9p²

    (7p² - 4p)² = (7p²)² + 2.4p.7p² + (-4p)² = 49p⁴ + 56p³ + 16p²

    (2m - ½)² = (2m)² + 2.(-½).2m + (-½)² = 4m² - 2m + ¼

    (4m + 1/m)² = (4m)² + 2.(1/m).4m + (1/m)² = 16m² + 8 + 1/m²

    (3m - ½m)² = (3m)² + 2.½m.3m + (½m)² = 9m² + 3m² + ¼m²


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