Tentukan f(x) jika: 1. f(x+3)=6-5x 2. f(2x-7)=4x-3 3. f(2-x) =x^2-10

jawab

1. f(x+3)= 6 - 5x
x+ 3 = y
x= y-3
f(y) = 6 - 5(y-3)
f(x)= 6 - 5(x-3)
f(x)= 6 - 5x + 15
f(x)= 21 - 5x

2. f(2x-7) = 4x - 3
2x-7 = y
x= (y +7)/2
f(y) = 4(y+7)/2 -3
f(x)= 4(x +7)/2  - 3
f(x)= 2(x+7) - 3
f(x)= 2x + 14 - 3
f(x)= 2x + 11

3. f(2-x) = x² -10
2-x = y
x  = 2 -y
f(y) = (2-y)² -10
f(x)= (2 -x)² -10
f(x)= 4 - 4x + x² -10
f(x)= x² - 4x - 6