integral 2x^2 akar 4x^3-5 dx

jawab

∫ 2x² √(4x³ -5) dx

u = 4x³ - 5
du = 12x² dx
2x² dx = 1/6 du

∫ 2x² √(4x³ -5) dx =  ∫ (1/6)(u)^(1/2) du
= 1/6.2/3. u^(3/2) + c
= 1/9 u√ u + c
= 1/9 (4x³ -5) √(4x³-5) + c