Jabarkan bentuk dari: a. (2a+3b)^2 b. (x-3y)^2 c. (2p-q)^2 Tolong bantu jawab dan pakai caranya ya....

a.(2a+3b)×(2a+3b)

=4a²+6ab+6ab+9b²

=4a²+12ab+3b²

b.(x-3y)×(x-3y)

=x²-3xy-3xy+9y

=x²-6xy+9y

c.(2p-q)×(2p-q)

=4p²-2pq-2pq+q²

=4p²-4pq+q²

moga moga bener dan bermanfaat

a.(2a+3b)^2= (2a+3b) (2a+3b)= 4a^2+6ab+6ab+9b^2= 4a^2+12ab+9b^2
b.(x-3y)^2= (x-3y) (x-3y)= x^2+3xy-3xy+9y^2= x^2+9y^2
c. (2p-q)^2 = (2p-q) (2p-q)= 4p^2-2pq-2pq+q^2= 4p^2-4pq+q^2