diketahui titik A (-3,2,2),B (-4,3,6),C (1,5,-4) hitung vektor A ke B

menghitung panjangnya kah?

vektor AB = B-A
                = (-4,3,6) - (-3,2,2)
               = (-1, 1, 4)
kalau panjang AB = [tex] \sqrt{(-1)^{2} + 1^{2} +4^2 } [/tex]
                            =[tex] \sqrt{18} [/tex]
                            =[tex]3 \sqrt{2} [/tex]