Nilai cos 255°adalah...
Matematika
ranaraniars
Pertanyaan
Nilai cos 255°adalah...
1 Jawaban
-
1. Jawaban Anonyme
Trigonometri.
cos (270° - θ°) = -sin θ°
cos 255° = -sin 15°
sin (α - β) = sin α cos β - cos α sin β
-sin 15° = -sin (45° - 30°)
= -(sin 45° cos 30° - cos 45° sin 30°)
= -[1/2 √2 (1/2 √3) - 1/2 √2 (1/2)]
= -1/4 √6 + 1/4 √2
= (√2 - √6) / 4