diketahui deret geometri 16+8+4+5+...+1/64 tentukan n dan sn nya

r = U2/U1
r = 8/16
r = 1/2

Un = a.r^(n-1)
1/64 = 16.(r^n):r
1/64 = 16.(r^n) : 1/2
1/64 = 32 (1/2^n)
1/(64.32) = 1/2^n
1/2^11 = 1/2^n
n = 11


Sn = a(1-(r^n)):(1-r)
= 16(1-(1/2^11):(1-1/2)
= 16 . ((2^11)-1):2^11:1/2
= 32 : 2^11.((2^11)-1)
= 2^5:2^11.((2^11)-1)
= ((2^11)-1):2^6
= (2.048-1):64
= 2.047/64

*note "^" = pangkat