tentukan persamaan garis yang sejajar 2×-3y+6=0 dan melalui titik ( 8,-6 )

Persamaan Garis Lurus.

ax + by + c = 0
2x - 3y + 6 = 0

ax + by = ax₁ + by₁
2x - 3y = 2(8) - 3(-6)
2x - 3y = 34
2x - 3y - 34 = 0