di jawab ya.pake cara.yang benar

Aljabar.

Harap buka dari situs web jika di aplikasi kode latexnya tidak terbaca!!! OKE???
Nomor 7
[tex]\displaystyle \frac{x^2+2x-3}{x^2+6x+9}~\frac{5x^2}{4x-4}\\ =\frac{(x-1)(x+3)}{(x+3)^2}~\frac{5x^2}{4x-4}\\ =\frac{5x^2(x-1)}{(x+3)(4x-4)}\\ =\frac{5x^2(x-1)}{4(x-1)(x+3)}\\ =\frac{5x^2}{4x+12}[/tex]

Nomor 8
[tex]\displaystyle \frac{2y+8}{y^2-4y+3} : \frac{y^2-16}{y^2-y-6}\\ =\frac{2y+8}{y^2-4y+3}~\frac{y^2-y-6}{y^2-16}\\ =\frac{2(y+4)(y-3)(y+2)}{(y-3)(y-1)(y-4)(y+4)}\\ =\frac{2(y+2)}{(y-4)(y-1)}\\ =\frac{2y+4}{y^2-5y+4}[/tex]