help me please 1. [tex] \lim_{x \to \ 3} \frac{x^3-6x^2+11x-6}{x^3-5x^2-8x+12}= [/tex] 2. [tex] \lim_{x \to \ 1} \frac{x-1}{ \sqrt{x+3} -2 } = [/tex] 3. [tex]
Matematika
Arlan
Pertanyaan
help me please
1.
[tex] \lim_{x \to \ 3} \frac{x^3-6x^2+11x-6}{x^3-5x^2-8x+12}= [/tex]
2.
[tex] \lim_{x \to \ 1} \frac{x-1}{ \sqrt{x+3} -2 } = [/tex]
3.
[tex] \lim_{x \to \ 1} \frac{ \sqrt{2x-1}- \sqrt{3x-2} }{2x-2} =[/tex]
#tlong ma cara krjax n serius please :'(
1.
[tex] \lim_{x \to \ 3} \frac{x^3-6x^2+11x-6}{x^3-5x^2-8x+12}= [/tex]
2.
[tex] \lim_{x \to \ 1} \frac{x-1}{ \sqrt{x+3} -2 } = [/tex]
3.
[tex] \lim_{x \to \ 1} \frac{ \sqrt{2x-1}- \sqrt{3x-2} }{2x-2} =[/tex]
#tlong ma cara krjax n serius please :'(
2 Jawaban
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1. Jawaban davedave
no 1. keluarkan pangkat tertinggi; jawabannya = 1
no2 dan 3 kali sekawan yang bentuk akar - akar dikalikan akar + akar / akar + akar atau sebaliknya -
2. Jawaban uranus99
2. lim x》1 [x-1]/[akar(x+3) - 2] = [1]/[1/(2akar(x+3))] =[1]/[1/4] =4 3. limx》1 [akar(2x-1) - akar(3x-2)]/[2x-2] ={2/[2akar(2x-1) -3/[2akar(3x-2)]}/2 ={2/2 - 3/2}/2 = (-1/4) cmiiw sorry ya berantakan haha