g(x)=√x³+1 nilai dari g^-1(g(0)) adalah

g(x) = √(x³+1)
g(0) = √(0³+1) = 1

y = √(x³+1)
y² = x³ + 1
x³ = y² - 1
x = ∛(y² - 1)

g⁻¹(x) = ∛(x² - 1)

g⁻¹(g(0))
= g⁻¹(1)
= ∛(1² - 1)
= ∛0
= 0