jika F (X)=(3-a)x+2 dan F (3)=5 maka tentukan a.bentuk fungsinya b.nilai F (1)

f(x) = (3 - a)x + 2
f(3) = 5 maka:
5 = (3 - a)(3) + 2
5 = 9 - 3a + 2
3a = 6
a = 2
maka bentuk fungsinya:
f(x) = x + 2

b. f(1) = 1 + 2
= 3

f(x) = (3-a) x +2
f(3) =5
f(3)= (3-a) 3 +2 = 5
(3-a) 5 = 5
15 - 5a = 5
-5a = 5-15
-5a = -10
a = -10 : -5
a = 2 
rumus fungsi = (3-2) x+2


f(1) = (3-2) 1 + 2 = ?
(3 - 2) 3 = ?
9 - 6 = 3