Tiga Buah Hambatan R¹=4 R²=2 Dan R³=8 Disusun paralel. Hitunglah hambatan pengganti, Jika Hambatan itu Dihubungkan dengan beda potensial V=24 Hitung Pula Kuat A

R₁ = 4 Ω
R₂ = 2 Ω
R₃ = 8 Ω

hambatan pengganti dengan rangkaian Pararel :
1/Rp = 1/R₁ + 1/R₂ + 1/R₃
1/Rp = 1/4 + 1/2 + 1/8
1/Rp = (2+4+1)/8
1/Rp = 7/8
Rp = 8/7 Ohm

kuat arus dengan beda potensial 24 V :
I = V/R
I = 24 ÷ 8/7
I = 24 × 7/8
I = 21 Ampere

LISTRIK DINAMIS

R₁ = 4, R₂ = 2, R₃ = 8 satuan ?
V = 24 V
Rₚ ?
i, i₁, i₂, i₃ ?

a][ hambatan pengganti
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/4 + 1/2 + 1/8
1/Rₚ = 2/8 + 4/8 + 1/8 = 7/8
Rₚ = 8/7 ohm ✓


b][ kuat arus

kuat arus induk
V = i Rₚ
24 ÷ i × 8/7
i = 24 × 7/8 = 21 A ✓

kuat arus cabang
i₁ : i₂ : i₃ = 1/R₁ : 1/R₂ : 1/R₃
i₁ : i₂ : i₃ = 1/4 : 1/2 : 1/8 = 2 : 4 : 1

i₁ = [2/(2+4+1)] × 21 = 6 A ✓
i₂ = [4/(2+4+1)] × 21 = 12 A ✓
i₃ = [1/(2+4+1)] × 21 = 3 A ✓